what is oxidized and what is reduced in this reaction? cu(s) + 2agno₃(aq) → cu(no₃)₂(aq) + 2ag(s) o cu is…

what is oxidized and what is reduced in this reaction? cu(s) + 2agno₃(aq) → cu(no₃)₂(aq) + 2ag(s) o cu is reduced and ag is oxidized. o ag is reduced and cu is oxidized. o no₃ is oxidized and cu is reduced. o ag is oxidized and no₃ is reduced. done
Answer
Explanation:
Step1: Determine oxidation states
Oxidation state of Cu in Cu(s) is 0. In Cu(NO₃)₂, for the nitrate ion NO₃⁻, oxygen has an oxidation state of - 2. Let the oxidation state of Cu be (x). Since the compound is neutral and there are 2 nitrate ions with a total charge of - 2 each, (x+2\times(-1)=0), so (x = + 2). Oxidation state of Ag in AgNO₃ is + 1 and in Ag(s) is 0. The oxidation state of N in NO₃⁻ is + 5 and of O is - 2, and they do not change in the reaction.
Step2: Identify oxidation and reduction
Oxidation is the increase in oxidation state. Cu goes from 0 to + 2, so Cu is oxidized. Reduction is the decrease in oxidation state. Ag goes from + 1 to 0, so Ag is reduced.
Answer:
Ag is reduced and Cu is oxidized.