part a\nhow many liters of a 2.35 m nacl solution will provide 69.6 g of nacl?\nexpress your answer with the…

part a\nhow many liters of a 2.35 m nacl solution will provide 69.6 g of nacl?\nexpress your answer with the appropriate units.\nvalue units\nsubmit request answer

part a\nhow many liters of a 2.35 m nacl solution will provide 69.6 g of nacl?\nexpress your answer with the appropriate units.\nvalue units\nsubmit request answer

Answer

Explanation:

Step1: Calculate moles of NaCl

The molar mass of NaCl is $M = 22.99\ g/mol+ 35.45\ g/mol=58.44\ g/mol$. The number of moles $n$ of NaCl is calculated by the formula $n=\frac{m}{M}$, where $m = 69.6\ g$. So $n=\frac{69.6\ g}{58.44\ g/mol}\approx1.19\ mol$.

Step2: Calculate volume of solution

The molarity $M$ of a solution is defined as $M=\frac{n}{V}$, where $M = 2.35\ M$ and $n$ is the number of moles. We can solve for the volume $V$, and $V=\frac{n}{M}$. Substituting $n = 1.19\ mol$ and $M=2.35\ mol/L$ into the formula, we get $V=\frac{1.19\ mol}{2.35\ mol/L}\approx0.506\ L$.

Answer:

0.506 L