what is the percent by mass of magnesium sulfate in mgso4·7h2o? use %element = \\frac{total mass of element…

Explanation:

Step1: Calculate molar mass of MgSO₄·7H₂O

The molar mass of Mg is 24.31 g/mol, S is 32.07 g/mol, O is 16.00 g/mol, and H is 1.01 g/mol. For MgSO₄·7H₂O: [ \begin{align*} M&=24.31+32.07+(4\times16.00)+7\times(2\times1.01 + 16.00)\ &=24.31+32.07 + 64.00+7\times(2.02 + 16.00)\ &=24.31+32.07+64.00 + 7\times18.02\ &=24.31+32.07+64.00+126.14\ &=246.52\ g/mol \end{align*} ]

Step2: Calculate molar mass of MgSO₄

[ \begin{align*} M_{MgSO_4}&=24.31+32.07+(4\times16.00)\ &=24.31+32.07 + 64.00\ &=120.38\ g/mol \end{align*} ]

Step3: Calculate percent - by - mass of MgSO₄ in MgSO₄·7H₂O

[ \begin{align*} %\text{MgSO}_4&=\frac{\text{molar mass of MgSO}_4}{\text{molar mass of MgSO}_4\cdot7\text{H}_2\text{O}}\times100%\ &=\frac{120.38}{246.52}\times100%\ &\approx48.83% \end{align*} ]

Answer:

48.83%