what is the percent by mass of water in na₂so₄·10h₂o? use %element = \\frac{total mass of element in…

what is the percent by mass of water in na₂so₄·10h₂o? use %element = \\frac{total mass of element in compound}{molar mass of compound}×100\no 5.59%\no 11.26%\no 44.08%\no 55.92%

what is the percent by mass of water in na₂so₄·10h₂o? use %element = \\frac{total mass of element in compound}{molar mass of compound}×100\no 5.59%\no 11.26%\no 44.08%\no 55.92%

Answer

Answer:

55.92%

Explanation:

Step1: Calculate molar mass of $Na_2SO_4\cdot10H_2O$

$M_{Na_2SO_4\cdot10H_2O}=2\times22.99 + 32.07+4\times16.00+10\times(2\times1.01 + 16.00)=322.19\ g/mol$

Step2: Calculate molar mass of water in $Na_2SO_4\cdot10H_2O$

$M_{10H_2O}=10\times(2\times1.01 + 16.00)=180.2\ g/mol$

Step3: Calculate percent - by - mass of water

$\text{Percent by mass of water}=\frac{180.2}{322.19}\times100%\approx55.92%$