2. if the percent yield of a reaction is 61.2% and the actual yield is 8.79 grams, what was the theoretical…

2. if the percent yield of a reaction is 61.2% and the actual yield is 8.79 grams, what was the theoretical yield?

2. if the percent yield of a reaction is 61.2% and the actual yield is 8.79 grams, what was the theoretical yield?

Answer

Explanation:

Step1: Recall percent - yield formula

Percent yield = $\frac{\text{Actual Yield}}{\text{Theoretical Yield}}\times100%$ Let the theoretical yield be $x$ grams. We know that percent yield = 61.2% = 0.612 and actual yield = 8.79 grams. So, $0.612=\frac{8.79}{x}$.

Step2: Solve for the theoretical yield $x$

Cross - multiply: $0.612x = 8.79$. Then $x=\frac{8.79}{0.612}$. Calculate $\frac{8.79}{0.612}\approx14.36$ grams.

Answer:

14.36 grams