in the periodic table below, shade all the elements for which the neutral atom has an outer electron…

in the periodic table below, shade all the elements for which the neutral atom has an outer electron configuration of $ms^{1}nd^{10}$, where $n$ and $m$ are integers, and $m = n + 1$.

in the periodic table below, shade all the elements for which the neutral atom has an outer electron configuration of $ms^{1}nd^{10}$, where $n$ and $m$ are integers, and $m = n + 1$.

Answer

Explanation:

Step1: Understand electron - configuration rule

The outer - electron configuration is (ms^{1}nd^{10}) with (m=n + 1).

Step2: Analyze periods and groups

For (n = 3), (m=4), the electron configuration is (4s^{1}3d^{10}), which is Cu (Copper). For (n = 4), (m = 5), the electron configuration is (5s^{1}4d^{10}), which is Ag (Silver). For (n = 5), (m=6), the electron configuration is (6s^{1}5d^{10}), which is Au (Gold).

Answer:

Shade Cu, Ag, Au on the periodic table.