what is the ph of the 0.00125 m naoh solution? remember that naoh is a strong base. a) ph = -0.00125 b) ph =…

what is the ph of the 0.00125 m naoh solution? remember that naoh is a strong base. a) ph = -0.00125 b) ph = 0.00125 c) ph = poh -14 = 2.9 - 14 = -11.1 d) ph = 14 - poh = 14 - 2.9 = 11.1

what is the ph of the 0.00125 m naoh solution? remember that naoh is a strong base. a) ph = -0.00125 b) ph = 0.00125 c) ph = poh -14 = 2.9 - 14 = -11.1 d) ph = 14 - poh = 14 - 2.9 = 11.1

Answer

Explanation:

Step1: Determine [OH⁻] concentration

Since NaOH is a strong - base and dissociates completely as NaOH → Na⁺+OH⁻, for a 0.00125 M NaOH solution, [OH⁻]=0.00125 M.

Step2: Calculate pOH

The formula for pOH is pOH = -log[OH⁻]. So, pOH=-log(0.00125). pOH = 2.9

Step3: Calculate pH

We know the relationship pH + pOH=14. So, pH = 14 - pOH. pH = 14 - 2.9 = 11.1

Answer:

d) pH = 14 - pOH = 14 - 2.9 = 11.1