ph = -logh+\naeen is drinking a beverage that has a ph of 3.3. marien is drinking a beverage that has a ph…

Explanation:

Step1: Find hydrogen - ion concentration of Aeen's drink

Given $pH = -\log[H^+]$, for Aeen's drink with $pH = 3.3$, we can rewrite the formula as $[H^+{Aeen}]=10^{-pH}$. So $[H^+{Aeen}]=10^{- 3.3}$.

Step2: Find hydrogen - ion concentration of Marien's drink

For Marien's drink with $pH = 2.7$, using the formula $[H^+]=10^{-pH}$, we get $[H^+_{Marien}]=10^{-2.7}$.

Step3: Calculate the ratio

The ratio of the hydrogen - ion concentration of Marien's drink to Aeen's drink is $\frac{[H^+{Marien}]}{[H^+{Aeen}]}=\frac{10^{-2.7}}{10^{-3.3}}$. According to the rule of exponents $\frac{a^m}{a^n}=a^{m - n}$, we have $\frac{10^{-2.7}}{10^{-3.3}}=10^{-2.7-(-3.3)}=10^{0.6}$.

Step4: Evaluate the result

Calculate $10^{0.6}\approx4$.

Answer:

4