ph = -logh+\naeen is drinking a beverage that has a ph of 3.3. marien is drinking a beverage that has a ph…

Explanation:

Step1: Find hydrogen - ion concentration for Aeen's drink

Given $pH = -\log[H^+]$, for Aeen's drink with $pH = 3.3$, we can rewrite the formula as $[H^+{Aeen}]=10^{-pH}$. So $[H^+{Aeen}]=10^{- 3.3}$.

Step2: Find hydrogen - ion concentration for Marien's drink

For Marien's drink with $pH = 2.7$, using the formula $[H^+]=10^{-pH}$, we get $[H^+_{Marien}]=10^{-2.7}$.

Step3: Find the ratio of hydrogen - ion concentrations

We want to find $\frac{[H^+{Marien}]}{[H^+{Aeen}]}$. Substitute the values we found: $\frac{10^{-2.7}}{10^{-3.3}}$. According to the rule of exponents $\frac{a^m}{a^n}=a^{m - n}$, so $\frac{10^{-2.7}}{10^{-3.3}}=10^{-2.7-(-3.3)} = 10^{0.6}$.

Step4: Calculate the value of $10^{0.6}$

$10^{0.6}\approx4$.

Answer:

4