what is the ph of a solution of h₂so₄ that has h₃o⁺ = 5.45 × 10⁻⁵ m? round to the nearest hundredth.
what is the ph of a solution of h₂so₄ that has h₃o⁺ = 5.45 × 10⁻⁵ m? round to the nearest hundredth.
Answer
Explanation:
Step1: Recall pH formula
The formula for pH is $pH = -\log[H_3O^+]$.
Step2: Substitute the given value
Substitute $[H_3O^+]=5.45\times 10^{-5}$ into the formula: $pH = -\log(5.45\times 10^{-5})$.
Step3: Calculate the value
Using a calculator, $\log(5.45\times 10^{-5})=-4.263$. Then $pH=-(-4.263) = 4.263$.
Step4: Round the result
Rounding 4.263 to the nearest hundredth gives 4.26.
Answer:
4.26