what is the poh of a solution of hno3 that has oh-=9.50×10-9 m? round to the nearest hundredth.

Explanation:

Step1: Recall pOH formula

The formula for pOH is $pOH = -\log[OH^-]$.

Step2: Substitute the given value

Substitute $[OH^-]=9.50\times 10^{-9}$ into the formula: $pOH = -\log(9.50\times 10^{-9})$.

Step3: Calculate the value

Using a calculator, $\log(9.50\times 10^{-9})=-8.02227$. Then $pOH=-(-8.02227) = 8.02227$.

Step4: Round the result

Rounding $8.02227$ to the nearest hundred - th gives $8.02$.

Answer:

$8.02$