practice atom diagrams: fill in the missing information and draw the\nelement helium\nelectrons:\nprotons…

practice atom diagrams: fill in the missing information and draw the\nelement helium\nelectrons:\nprotons: 2\nneutrons:\nmass 3 amu\ncharge 0 (neutral atom)\n\nelement\nelectrons:\nprotons: 6\nneutrons:\nmass 11 amu\ncharge 0 (neutral atom)\n\nelement\nelectrons:\nprotons: 9\nneutrons: 8\nmass amu\ncharge 0 (neutral atom)
Answer
Explanation:
Step1: Recall atomic - structure relationships
In a neutral atom, the number of electrons equals the number of protons. The mass number is the sum of protons and neutrons.
Step2: Solve for the first atom (Helium)
Since the number of protons is 2 and it's a neutral atom, the number of electrons is 2. Using the formula $Mass\ number=Protons + Neutrons$, we can find the number of neutrons. Given mass number = 3 amu and protons = 2, then $Neutrons=Mass\ number - Protons=3 - 2 = 1$.
Step3: Solve for the second atom
The number of protons is 6 and it's a neutral atom, so the number of electrons is 6. Using $Mass\ number=Protons + Neutrons$, with mass number = 11 amu and protons = 6, we get $Neutrons=11 - 6 = 5$. The element with 6 protons is Carbon.
Step4: Solve for the third atom
Since it's a neutral atom with 9 protons, the number of electrons is 9. Using $Mass\ number=Protons + Neutrons$, with protons = 9 and neutrons = 8, the mass number is $9 + 8=17$ amu. The element with 9 protons is Fluorine.
Answer:
| Element | Helium | Carbon | Fluorine |
|---|---|---|---|
| Electrons: | 2 | 6 | 9 |
| Protons: | 2 | 6 | 9 |
| Neutrons: | 1 | 5 | 8 |
| Mass | 3 amu | 11 amu | 17 amu |
| Charge | 0 (Neutral Atom) | 0 (Neutral Atom) | 0 (Neutral Atom) |