q21.2.5\nwrite the nuclide notation, including charge if applicable, for atoms with the following…

q21.2.5\nwrite the nuclide notation, including charge if applicable, for atoms with the following characteristics:\na. 25 protons, 20 neutrons, 24 electrons\nb. 45 protons, 24 neutrons, 43 electrons\nc. 53 protons, 89 neutrons, 54 electrons\nd. 97 protons, 146 neutrons, 97 electrons

q21.2.5\nwrite the nuclide notation, including charge if applicable, for atoms with the following characteristics:\na. 25 protons, 20 neutrons, 24 electrons\nb. 45 protons, 24 neutrons, 43 electrons\nc. 53 protons, 89 neutrons, 54 electrons\nd. 97 protons, 146 neutrons, 97 electrons

Answer

Explanation:

Step1: Recall the nuclide notation formula

The nuclide notation is ({Z}^{A}X^{n+}) or ({Z}^{A}X^{n-}), where (Z) is the atomic number (number of protons), (A) is the mass number ((A = \text{number of protons}+\text{number of neutrons})), (X) is the element symbol, and (n) is the charge ((n=\text{number of protons}-\text{number of electrons}))

Step2: Find element symbol for each case

  • Case (a):
    • (Z = 25) (protons). The element with (Z = 25) is manganese ((Mn))
    • (A=25 + 20=45)
    • (n=25-24 = 1+)
    • Nuclide notation: (_{25}^{45}Mn^{1+})
  • Case (b):
    • (Z = 45) (protons). The element with (Z = 45) is rhodium ((Rh))
    • (A=45 + 24=69)
    • (n=45-43 = 2+)
    • Nuclide notation: (_{45}^{69}Rh^{2+})
  • Case (c):
    • (Z = 53) (protons). The element with (Z = 53) is iodine ((I))
    • (A=53 + 89=142)
    • (n=53-54=- 1)
    • Nuclide notation: (_{53}^{142}I^{-})
  • Case (d):
    • (Z = 97) (protons). The element with (Z = 97) is berkelium ((Bk))
    • (A=97+146 = 243)
    • (n=97 - 97=0)
    • Nuclide notation: (_{97}^{243}Bk)

Answer:

a. ({25}^{45}Mn^{1+}) b. ({45}^{69}Rh^{2+}) c. ({53}^{142}I^{-}) d. ({97}^{243}Bk)