question 10\n2 pts\na metal sphere weigh 2.403 g is added to 15.0 ml water in graduated cylinder. the water…

question 10\n2 pts\na metal sphere weigh 2.403 g is added to 15.0 ml water in graduated cylinder. the water level rise to 16.7 ml. calculate the density of the metal.\n0.92 g/ml\n2.8 g/ml\n1.8 g/ml\n1.4 g/ml

question 10\n2 pts\na metal sphere weigh 2.403 g is added to 15.0 ml water in graduated cylinder. the water level rise to 16.7 ml. calculate the density of the metal.\n0.92 g/ml\n2.8 g/ml\n1.8 g/ml\n1.4 g/ml

Answer

Explanation:

Step1: Find volume of metal

The volume of the metal is equal to the volume of water displaced. Volume of water displaced $V=V_{final}-V_{initial}$. So, $V = 16.7\ mL - 15.0\ mL=1.7\ mL$.

Step2: Calculate density

The density formula is $\rho=\frac{m}{V}$, where $m = 2.403\ g$ and $V = 1.7\ mL$. Then $\rho=\frac{2.403\ g}{1.7\ mL}\approx1.4\ g/mL$.

Answer:

1.4 g/mL