question 5\n10 pts\nwhich one of the following aqueous solutions has the ph lower than 7?\no 0.01 m h2so4\no…

question 5\n10 pts\nwhich one of the following aqueous solutions has the ph lower than 7?\no 0.01 m h2so4\no 20% sucrose (table sugar, c12h22o11)\no 0.01 m koh\no 0.01 m kcl\n\nquestion 6\n10 pts\nwhich two species are a conjugate acid/base pair?\no h2co3/hco3-\no hcl/hbr\no koh/naoh\no h3po4/po4^3-

question 5\n10 pts\nwhich one of the following aqueous solutions has the ph lower than 7?\no 0.01 m h2so4\no 20% sucrose (table sugar, c12h22o11)\no 0.01 m koh\no 0.01 m kcl\n\nquestion 6\n10 pts\nwhich two species are a conjugate acid/base pair?\no h2co3/hco3-\no hcl/hbr\no koh/naoh\no h3po4/po4^3-

Answer

Explanation:

Question 5:

Step1: Analyze acid - base nature

Acids have pH < 7 in aqueous solutions. $H_2SO_4$ is a strong acid, sucrose is a non - electrolyte, KOH is a strong base and KCl is a neutral salt.

Step2: Determine pH

$H_2SO_4$ dissociates to release $H^+$ ions, so its solution has pH < 7.

Question 6:

Step1: Recall conjugate acid - base pair concept

A conjugate acid - base pair differs by one $H^+$.

Step2: Identify pair

$H_2CO_3$ can lose a $H^+$ to form $HCO_3^-$, so $H_2CO_3/HCO_3^-$ is a conjugate acid - base pair.

Answer:

Question 5: 0.01 M $H_2SO_4$ Question 6: $H_2CO_3/HCO_3^-$