question 22 of 31 what is the balanced form of the chemical equation shown below? c6h12o6(s) + o2(g) →…

question 22 of 31 what is the balanced form of the chemical equation shown below? c6h12o6(s) + o2(g) → h2o(l) + co2(g) a. c6h12o6(s) + o2(g) → 12h2o(l) + 6co2(g) b. ch2o(s) + o2(g) → h2o(l) + co2(g) c. c6h12o6(s) + o2(g) → h2o(l) + co2(g) d. c6h12o6(s) + 6o2(g) → 6h2o(l) + 6co2(g)

question 22 of 31 what is the balanced form of the chemical equation shown below? c6h12o6(s) + o2(g) → h2o(l) + co2(g) a. c6h12o6(s) + o2(g) → 12h2o(l) + 6co2(g) b. ch2o(s) + o2(g) → h2o(l) + co2(g) c. c6h12o6(s) + o2(g) → h2o(l) + co2(g) d. c6h12o6(s) + 6o2(g) → 6h2o(l) + 6co2(g)

Answer

Explanation:

Step1: Balance carbon atoms

In $C_6H_{12}O_6$, there are 6 carbon atoms. On the right - hand side, $CO_2$ contains carbon. To balance carbon, we need 6 moles of $CO_2$ since each $CO_2$ has 1 carbon atom.

Step2: Balance hydrogen atoms

In $C_6H_{12}O_6$, there are 12 hydrogen atoms. Each $H_2O$ has 2 hydrogen atoms. So we need 6 moles of $H_2O$ to balance the hydrogen atoms.

Step3: Balance oxygen atoms

On the left - hand side, in $C_6H_{12}O_6$ there are 6 oxygen atoms and in $O_2$ we have oxygen atoms. On the right - hand side, in 6 moles of $H_2O$ there are 6 oxygen atoms and in 6 moles of $CO_2$ there are 12 oxygen atoms, for a total of 18 oxygen atoms on the right - hand side. Since $C_6H_{12}O_6$ has 6 oxygen atoms, we need 6 moles of $O_2$ (each $O_2$ has 2 oxygen atoms, so 6 moles of $O_2$ have 12 oxygen atoms) to balance the oxygen atoms. The balanced equation is $C_6H_{12}O_6(s)+6O_2(g)\rightarrow6H_2O(l) + 6CO_2(g)$.

Answer:

D. $C_6H_{12}O_6(s)+6O_2(g)\rightarrow6H_2O(l)+6CO_2(g)$