question 23 (2 points)\nname the organic product that is formed when 2 - methylpent - 1 - ene and hcl react.

Explanation:

Step1: Analyze the reaction type

This is an electrophilic addition reaction of an alkene (2 - methylpent - 1 - ene) with HCl. According to Markovnikov's rule, the hydrogen atom from HCl adds to the carbon of the double bond that has more hydrogen atoms attached.

Step2: Determine the product structure

The double bond in 2 - methylpent - 1 - ene (CH_2 = C(CH_3)CH_2CH_2CH_3) reacts. The H from HCl adds to the (CH_2) carbon (since it has more H atoms compared to the (C(CH_3)) carbon of the double bond). The Cl adds to the (C(CH_3)) carbon. The resulting structure is (CH_3C(Cl)(CH_3)CH_2CH_2CH_3)

Step3: Name the product

Using IUPAC nomenclature for alkyl halides. The longest carbon chain has 5 carbon atoms (pentane). There is a methyl group at the second carbon and a chlorine atom at the second carbon. So the name is 2 - chloro - 2 - methylpentane.

Answer:

2 - chloro - 2 - methylpentane