question 26\n1 pts\nthere are ______ orbitals in the third shell.\n9\n25\n16\n1\n4\nquestion 27\n1…

question 26\n1 pts\nthere are ______ orbitals in the third shell.\n9\n25\n16\n1\n4\nquestion 27\n1 pts\nar4s²3d¹⁰4p³ is the electron configuration of a(n) ______ atom.\nsb\nsn\nas\np\nv

question 26\n1 pts\nthere are ______ orbitals in the third shell.\n9\n25\n16\n1\n4\nquestion 27\n1 pts\nar4s²3d¹⁰4p³ is the electron configuration of a(n) ______ atom.\nsb\nsn\nas\np\nv

Answer

Explanation:

Step1: Recall orbital - counting formula

The number of orbitals in a shell with principal quantum number (n) is given by (n^{2}). For the third shell, (n = 3).

Step2: Calculate number of orbitals

Substitute (n = 3) into the formula (n^{2}). So, (3^{2}=9).

Step3: Analyze electron - configuration for Question 27

The electron - configuration ([Ar]4s^{2}3d^{10}4p^{3}) means the atom has the electron configuration of argon ((Ar), which has 18 electrons) plus (2 + 10+3=15) more electrons. So the total number of electrons is (18 + 15=33).

Step4: Identify the element

The element with 33 electrons has an atomic number of 33, which is arsenic ((As)).

Answer:

Question 26: A. 9 Question 27: C. As