question 2\nwhen 0.663 mol of h₂so₄ reacts according to the following equation, how many molecules of water…

question 2\nwhen 0.663 mol of h₂so₄ reacts according to the following equation, how many molecules of water would be produced?\n2 nahco₃ + h₂so₄ → na₂so₄ + 2 h₂o + 2 co₂\nmolecules of h₂o\nquestion 3\nalcoholic fermentation converts glucose (c₆h₁₂o₆) into ethanol (c₂h₅oh) and carbon dioxide (co₂). what mass of carbon dioxide can be formed from the alcoholic fermentation of 35.5 g of glucose?\ng co₂

question 2\nwhen 0.663 mol of h₂so₄ reacts according to the following equation, how many molecules of water would be produced?\n2 nahco₃ + h₂so₄ → na₂so₄ + 2 h₂o + 2 co₂\nmolecules of h₂o\nquestion 3\nalcoholic fermentation converts glucose (c₆h₁₂o₆) into ethanol (c₂h₅oh) and carbon dioxide (co₂). what mass of carbon dioxide can be formed from the alcoholic fermentation of 35.5 g of glucose?\ng co₂

Answer

Explanation:

Step1: Determine mole ratio

From the equation (2NaHCO_{3}+H_{2}SO_{4}\to Na_{2}SO_{4}+2H_{2}O + 2CO_{2}), the mole ratio of (H_{2}SO_{4}) to (H_{2}O) is (1:2).

Step2: Calculate moles of (H_{2}O)

If (n(H_{2}SO_{4})=0.663\space mol), then (n(H_{2}O)=2\times n(H_{2}SO_{4}) = 2\times0.663\space mol=1.326\space mol)

Step3: Calculate number of molecules

Using Avogadro's number (N = n\times N_{A}), where (N_{A}=6.022\times 10^{23}\space mol^{-1}) (N(H_{2}O)=1.326\space mol\times6.022\times 10^{23}\space mol^{-1}=7.985\times 10^{23})

Answer:

(7.99\times 10^{23})