question 1\nwhat is the complete ionic equation for the reaction of na₂co₃ and hcl in water?\ndont forget to…

question 1\nwhat is the complete ionic equation for the reaction of na₂co₃ and hcl in water?\ndont forget to balance the reaction equation.\n\n○ 2na⁺(aq) + co₃²⁻(aq) + 2h⁺(aq) + 2cl⁻(aq) ==> 2na⁺(aq) + 2cl⁻(aq) + h₂co₂(aq)\n○ 2na⁺(aq) + co₃²⁻(aq) + 2h⁺(aq) + 2cl⁻(aq) ==> 2nacl(aq) + co₂(g) + h₂o(l)\n○ 2na⁺(aq) + co₃²⁻(aq) + 2h⁺(aq) + 2cl⁻(aq) ==> 2na⁺(aq) + 2cl⁻(aq) + co₂(g) + h₂o(l)\n○ 2na⁺(aq) + co₃²⁻(aq) + 2h⁺(aq) + 2cl⁻(aq) ==> 2nacl(s) + co₂(g) + h₂o(l)\n○ na₂co₃(aq) + 2hcl(aq) ==> 2nacl(aq) + co₂(g) + h₂o(l)

question 1\nwhat is the complete ionic equation for the reaction of na₂co₃ and hcl in water?\ndont forget to balance the reaction equation.\n\n○ 2na⁺(aq) + co₃²⁻(aq) + 2h⁺(aq) + 2cl⁻(aq) ==> 2na⁺(aq) + 2cl⁻(aq) + h₂co₂(aq)\n○ 2na⁺(aq) + co₃²⁻(aq) + 2h⁺(aq) + 2cl⁻(aq) ==> 2nacl(aq) + co₂(g) + h₂o(l)\n○ 2na⁺(aq) + co₃²⁻(aq) + 2h⁺(aq) + 2cl⁻(aq) ==> 2na⁺(aq) + 2cl⁻(aq) + co₂(g) + h₂o(l)\n○ 2na⁺(aq) + co₃²⁻(aq) + 2h⁺(aq) + 2cl⁻(aq) ==> 2nacl(s) + co₂(g) + h₂o(l)\n○ na₂co₃(aq) + 2hcl(aq) ==> 2nacl(aq) + co₂(g) + h₂o(l)

Answer

Explanation:

Step1: Recall Ionic Equation Rules

Complete ionic equations show all soluble ionic compounds as dissociated ions. ( \text{Na}_2\text{CO}_3 ) (soluble) dissociates into ( 2\text{Na}^+ + \text{CO}_3^{2-} ), ( \text{HCl} ) (soluble) dissociates into ( \text{H}^+ + \text{Cl}^- ), ( \text{NaCl} ) (soluble) dissociates into ( \text{Na}^+ + \text{Cl}^- ). The reaction produces ( \text{CO}_2 ), ( \text{H}_2\text{O} ), and ( \text{NaCl} ).

Step2: Analyze Each Option

  • Option 1: ( \text{H}_2\text{CO}_2 ) is incorrect (should be ( \text{CO}_2 + \text{H}_2\text{O} ) from ( \text{H}_2\text{CO}_3 ) decomposition).
  • Option 2: ( \text{NaCl} ) is not dissociated (should be ( \text{Na}^+ + \text{Cl}^- ) in complete ionic).
  • Option 3: ( 2\text{Na}^+ + \text{CO}_3^{2-} + 2\text{H}^+ + 2\text{Cl}^- \rightarrow 2\text{Na}^+ + 2\text{Cl}^- + \text{CO}_2 + \text{H}_2\text{O} ) – correctly dissociates reactants and products (soluble ( \text{NaCl} ) as ions, ( \text{CO}_2 ) and ( \text{H}_2\text{O} ) as is).
  • Option 4: ( \text{NaCl} ) is solid (incorrect, ( \text{NaCl} ) is aqueous and soluble).
  • Option 5: Molecular equation, not complete ionic.

Answer:

( 2\text{Na}^+{(aq)} + \text{CO}3^{2-}{(aq)} + 2\text{H}^+{(aq)} + 2\text{Cl}^-{(aq)} ==> 2\text{Na}^+{(aq)} + 2\text{Cl}^-{(aq)} + \text{CO}{2(g)} + \text{H}2\text{O}{(l)} ) (the third option in the list)