question 1 (2 points)\nhow many moles of solute in 2.00 l of a 3.00 m solution?\nthe solute could be…

question 1 (2 points)\nhow many moles of solute in 2.00 l of a 3.00 m solution?\nthe solute could be anything, and the solvent is usually water.\nthe concentration will always be the conversion factor. m stands for mol/l.\n__1__ mol\n(__2__ l)(---------) = __3__ mol\n__4__ l\na. 0 b. 1 c. 2 d. 3 e. 4 f. 5\ng. 6 h. 234 i. 58.44 j. 100. k. 1.71\nl. 0.856 m. 10.0

question 1 (2 points)\nhow many moles of solute in 2.00 l of a 3.00 m solution?\nthe solute could be anything, and the solvent is usually water.\nthe concentration will always be the conversion factor. m stands for mol/l.\n__1__ mol\n(__2__ l)(---------) = __3__ mol\n__4__ l\na. 0 b. 1 c. 2 d. 3 e. 4 f. 5\ng. 6 h. 234 i. 58.44 j. 100. k. 1.71\nl. 0.856 m. 10.0

Answer

Explanation:

Step1: Recall the formula for molarity

Molarity (M=\frac{n}{V}), where (n) is the number of moles of solute and (V) is the volume of the solution in liters. Rearranging for (n) gives (n = M\times V).

Step2: Substitute the given values

Given (M = 3.00\space mol/L) and (V=2.00\space L). Then (n=(3.00\space mol/L)\times(2.00\space L))

Answer:

  1. (3.00)
  2. (2.00)
  3. (6.00)
  4. (1)

The final answer for the number of moles (blank 3) is (G.6)