question 2 (2 points)\nwhen one mole of each reactant is mixed, which reactant is the limiting…

question 2 (2 points)\nwhen one mole of each reactant is mixed, which reactant is the limiting reagent?\nh₂so₃ + lioh → h₂o + li₂so₃\n○li₂so₃\n○h₂so₃\n○h₂o\n○there is no limiting reactant\n○lioh

question 2 (2 points)\nwhen one mole of each reactant is mixed, which reactant is the limiting reagent?\nh₂so₃ + lioh → h₂o + li₂so₃\n○li₂so₃\n○h₂so₃\n○h₂o\n○there is no limiting reactant\n○lioh

Answer

Explanation:

Step1: Balance the chemical equation

$H_2SO_3 + 2LiOH\rightarrow 2H_2O+Li_2SO_3$

Step2: Analyze mole - ratio

From the balanced equation, the mole - ratio of $H_2SO_3$ to $LiOH$ is $1:2$. Given 1 mole of each reactant, for 1 mole of $H_2SO_3$, 2 moles of $LiOH$ are required. But we only have 1 mole of $LiOH$.

Answer:

E. LiOH