the reactants and products of cellular respiration are made of the same amounts of hydrogen, carbon, and…

the reactants and products of cellular respiration are made of the same amounts of hydrogen, carbon, and oxygen atoms. when 1 molecule of glucose ($c_6h_{12}o_6$) reacts with 6 molecules of oxygen gas ($o_2$), the atoms in those molecules are rearranged to produce 6 molecules of carbon dioxide gas ($co_2$) and 6 molecules of water ($h_2o$).\nwhich chemical equation is balanced and represents the overall process of cellular respiration?\n$c_6h_{12}o_6 + 6o_2 \\longrightarrow co_2 + 6h_2o$ $c_6h_{12}o_6 + 6o_2 \\longrightarrow 6co_2 + 6h_2o$\n$6c_6h_{12}o_6 + 6o_2 \\longrightarrow 6co_2 + 6h_2o$ $6c_6h_{12}o_6 + o_2 \\longrightarrow 6co_2 + h_2o$

the reactants and products of cellular respiration are made of the same amounts of hydrogen, carbon, and oxygen atoms. when 1 molecule of glucose ($c_6h_{12}o_6$) reacts with 6 molecules of oxygen gas ($o_2$), the atoms in those molecules are rearranged to produce 6 molecules of carbon dioxide gas ($co_2$) and 6 molecules of water ($h_2o$).\nwhich chemical equation is balanced and represents the overall process of cellular respiration?\n$c_6h_{12}o_6 + 6o_2 \\longrightarrow co_2 + 6h_2o$ $c_6h_{12}o_6 + 6o_2 \\longrightarrow 6co_2 + 6h_2o$\n$6c_6h_{12}o_6 + 6o_2 \\longrightarrow 6co_2 + 6h_2o$ $6c_6h_{12}o_6 + o_2 \\longrightarrow 6co_2 + h_2o$

Answer

To determine the balanced chemical equation for cellular respiration, we analyze the number of each atom (C, H, O) on both sides of the equation.

Step 1: Analyze the first option: $\boldsymbol{\ce{C6H12O6 + 6O2 -> CO2 + 6H2O}}$

  • Carbon (C): Left = 6, Right = 1 (unbalanced).
  • Hydrogen (H): Left = 12, Right = ( 6 \times 2 = 12 ) (balanced).
  • Oxygen (O): Left = ( 6 + (6 \times 2) = 18 ), Right = ( (2) + (6 \times 1) = 8 ) (unbalanced).

Step 2: Analyze the second option: $\boldsymbol{\ce{C6H12O6 + 6O2 -> 6CO2 + 6H2O}}$

  • Carbon (C): Left = 6, Right = ( 6 \times 1 = 6 ) (balanced).
  • Hydrogen (H): Left = 12, Right = ( 6 \times 2 = 12 ) (balanced).
  • Oxygen (O): Left = ( 6 + (6 \times 2) = 18 ), Right = ( (6 \times 2) + (6 \times 1) = 18 ) (balanced).

Step 3: Analyze the third option: $\boldsymbol{\ce{6C6H12O6 + 6O2 -> 6CO2 + 6H2O}}$

  • Carbon (C): Left = ( 6 \times 6 = 36 ), Right = ( 6 \times 1 = 6 ) (unbalanced).
  • Hydrogen (H): Left = ( 6 \times 12 = 72 ), Right = ( 6 \times 2 = 12 ) (unbalanced).
  • Oxygen (O): Left = ( (6 \times 6) + (6 \times 2) = 48 ), Right = ( (6 \times 2) + (6 \times 1) = 18 ) (unbalanced).

Step 4: Analyze the fourth option: $\boldsymbol{\ce{6C6H12O6 + O2 -> 6CO2 + H2O}}$

  • Carbon (C): Left = ( 6 \times 6 = 36 ), Right = ( 6 \times 1 = 6 ) (unbalanced).
  • Hydrogen (H): Left = ( 6 \times 12 = 72 ), Right = ( 2 ) (unbalanced).
  • Oxygen (O): Left = ( (6 \times 6) + 2 = 38 ), Right = ( (6 \times 2) + 1 = 13 ) (unbalanced).

Only the second equation (( \ce{C6H12O6 + 6O2 -> 6CO2 + 6H2O} )) has equal numbers of C, H, and O atoms on both sides.

Answer: $\boldsymbol{\ce{C6H12O6 + 6O2 -> 6CO2 + 6H2O}}$ (the second option in the given choices)