rubidium has an atomic number of 37 and a mass number of 85. how many protons, neutrons, and electrons does…

rubidium has an atomic number of 37 and a mass number of 85. how many protons, neutrons, and electrons does an ion of rubidium with a 1+ charge have? (1 point) o 37 protons, 48 neutrons, 36 electrons o 37 protons, 48 neutrons, 38 electrons o 48 protons, 37 neutrons, 38 electrons o 48 protons, 37 neutrons, 36 electrons
Answer
Explanation:
Step1: Recall atomic - related concepts
The atomic number (Z) is equal to the number of protons. Given that the atomic number of rubidium is 37, the number of protons is 37.
Step2: Calculate the number of neutrons
The mass number (A) is the sum of protons and neutrons. Given A = 85 and Z = 37, the number of neutrons (n=A - Z=85 - 37 = 48).
Step3: Determine the number of electrons in a + 1 ion
In a neutral atom, the number of electrons is equal to the number of protons. For a (Rb^+) ion with a + 1 charge, it has lost one electron. So the number of electrons is (37-1 = 36).
Answer:
37 protons, 48 neutrons, and 36 electrons