a sample of a gas has a pressure of 1.01 atm when the volume is 256 ml. what is the pressure of the gas when…

Answer:

A. 2.08 atm

Explanation:

Step1: Apply Boyle's Law

Boyle's Law is (P_1V_1 = P_2V_2). Here, (P_1 = 1.01) atm, (V_1=256) mL, (V_2 = 118) mL. We need to find (P_2).

Step2: Rearrange the formula for (P_2)

From (P_1V_1 = P_2V_2), we get (P_2=\frac{P_1V_1}{V_2}).

Step3: Substitute the values

Substitute (P_1 = 1.01) atm, (V_1 = 256) mL, (V_2=118) mL into the formula: (P_2=\frac{1.01\times256}{118}).

Step4: Calculate (P_2)

(1.01\times256 = 258.56), then (\frac{258.56}{118}\approx2.08) atm.