a sample of grape juice has a hydroxide ion concentration of 1.4 x 10-10 m. when you solve for ph, what…

a sample of grape juice has a hydroxide ion concentration of 1.4 x 10-10 m. when you solve for ph, what value do you obtain? round to the nearest tenth.
Answer
Explanation:
Step1: Calculate pOH
pOH is calculated using the formula $pOH = -\log[OH^-]$. Given $[OH^-]=1.4\times 10^{- 10}\ M$. $pOH=-\log(1.4\times 10^{-10})$ Using the logarithm property $\log(ab)=\log a+\log b$, we have $pOH = -(\log1.4+\log(10^{-10}))$. Since $\log(10^{-10})=- 10$ and $\log1.4\approx0.146$, then $pOH\approx - (0.146 - 10)=9.854$.
Step2: Calculate pH
We know the relationship $pH + pOH=14$. So $pH=14 - pOH$. Substitute $pOH = 9.854$ into the formula, we get $pH=14 - 9.854 = 4.146\approx4.1$.
Answer:
$4.1$