sample problem b for more help, go to the math tutor at the end of this chapter. in photosynthesis, plants…

sample problem b for more help, go to the math tutor at the end of this chapter. in photosynthesis, plants use energy from the sun to produce glucose, c6h12o6, and oxygen from the reaction of carbon dioxide and water. what mass, in grams, of glucose is produced when 3.00 mol of water react with carbon dioxide?

sample problem b for more help, go to the math tutor at the end of this chapter. in photosynthesis, plants use energy from the sun to produce glucose, c6h12o6, and oxygen from the reaction of carbon dioxide and water. what mass, in grams, of glucose is produced when 3.00 mol of water react with carbon dioxide?

Answer

Explanation:

Step1: Write the balanced chemical equation

The balanced equation for photosynthesis is $6CO_2 + 6H_2O\rightarrow C_6H_{12}O_6+6O_2$.

Step2: Determine the mole - ratio

From the balanced equation, the mole - ratio of $H_2O$ to $C_6H_{12}O_6$ is 6:1.

Step3: Calculate the moles of glucose

Given $n_{H_2O}=3.00\ mol$. Using the mole - ratio, $n_{C_6H_{12}O_6}=\frac{1}{6}\times n_{H_2O}=\frac{1}{6}\times3.00\ mol = 0.500\ mol$.

Step4: Calculate the molar mass of glucose

The molar mass of $C_6H_{12}O_6$: $M=(6\times12.01 + 12\times1.01+6\times16.00)\ g/mol=180.18\ g/mol$.

Step5: Calculate the mass of glucose

Using the formula $m = n\times M$, $m_{C_6H_{12}O_6}=n_{C_6H_{12}O_6}\times M_{C_6H_{12}O_6}=0.500\ mol\times180.18\ g/mol = 90.09\ g$.

Answer:

90.09 g