scientific notation\n2) complete the following, writing your answer in standard scier\na) 0.00918 = \n b)…

scientific notation\n2) complete the following, writing your answer in standard scier\na) 0.00918 = \n b) 754,000 = \n c) 101.325 x 10² = \n d) (2 x 10²)(4 x 10¹²) = \n e) $\frac{9\times10^{8}}{3\times10^{3}}$ = \natoms, elements, compounds & molecules\nthe particle diagram la\nthe particle diagram la\nfigure 1.\nfigure 2.\neach particle in figure 1 is a(n) (atom\neach particle in figure 2 is a(n) (atom\ndensity\n4) the density of an unknown metal was found experimentally usin given below.\nvolume of water in the graduated cylinder 55.0 m\nvolume of water in the graduated cylinder with metal 61.5 m

scientific notation\n2) complete the following, writing your answer in standard scier\na) 0.00918 = \n b) 754,000 = \n c) 101.325 x 10² = \n d) (2 x 10²)(4 x 10¹²) = \n e) $\frac{9\times10^{8}}{3\times10^{3}}$ = \natoms, elements, compounds & molecules\nthe particle diagram la\nthe particle diagram la\nfigure 1.\nfigure 2.\neach particle in figure 1 is a(n) (atom\neach particle in figure 2 is a(n) (atom\ndensity\n4) the density of an unknown metal was found experimentally usin given below.\nvolume of water in the graduated cylinder 55.0 m\nvolume of water in the graduated cylinder with metal 61.5 m

Answer

Explanation:

Step1: Convert 0.00918 to scientific - notation

Move the decimal point 3 places to the right. So, $0.00918 = 9.18\times10^{-3}$.

Step2: Convert 754000 to scientific - notation

Move the decimal point 5 places to the left. So, $754000=7.54\times 10^{5}$.

Step3: Simplify $101.325\times10^{2}$

First, $101.325\times10^{2}=10132.5$. Then, move the decimal point 4 places to the left, getting $1.01325\times 10^{4}$.

Step4: Multiply $(2\times10^{2})(4\times10^{12})$

Use the rule $a\times10^{m}\times b\times10^{n}=ab\times10^{m + n}$. So, $(2\times10^{2})(4\times10^{12})=(2\times4)\times10^{2 + 12}=8\times10^{14}$.

Step5: Simplify $\frac{9\times10^{8}}{3\times10^{3}}$

Use the rule $\frac{a\times10^{m}}{b\times10^{n}}=\frac{a}{b}\times10^{m - n}$. So, $\frac{9\times10^{8}}{3\times10^{3}}=\frac{9}{3}\times10^{8 - 3}=3\times10^{5}$.

Answer:

a) $9.18\times10^{-3}$ b) $7.54\times 10^{5}$ c) $1.01325\times 10^{4}$ d) $8\times10^{14}$ e) $3\times10^{5}$