a sealed container can hold 0.325 l of gas at 1.00 atm and 293 k. use the ideal gas law, pv = nrt, to…

a sealed container can hold 0.325 l of gas at 1.00 atm and 293 k. use the ideal gas law, pv = nrt, to calculate the number of moles of gas the container can hold. p = 1.00 atm v = 0.325 l r = 0.0821 l·atm/mol·k t = 293 k n = ? ? mol gas

a sealed container can hold 0.325 l of gas at 1.00 atm and 293 k. use the ideal gas law, pv = nrt, to calculate the number of moles of gas the container can hold. p = 1.00 atm v = 0.325 l r = 0.0821 l·atm/mol·k t = 293 k n = ? ? mol gas

Answer

Explanation:

Step1: Rearrange ideal - gas law

Given $PV = nRT$, we can solve for $n$ by rearranging the formula to $n=\frac{PV}{RT}$.

Step2: Substitute values

Substitute $P = 1.00$ atm, $V = 0.325$ L, $R=0.0821$ L·atm/mol·K, and $T = 293$ K into the formula: $n=\frac{1.00\ atm\times0.325\ L}{0.0821\ L\cdot atm/mol\cdot K\times293\ K}$

Step3: Calculate

$n=\frac{0.325}{0.0821\times293}=\frac{0.325}{24.0553}\approx0.0135$ mol

Answer:

$0.0135$