select the correct answer.\na compound has a molecular weight of 112.124 atomic mass units and the empirical…

select the correct answer.\na compound has a molecular weight of 112.124 atomic mass units and the empirical formula c₃h₄o. what is the molecular formula of the compound?\nuse the periodic table to help you\n\n○ a. c₆h₈o\n○ b. c₉h₁₂o₃\n○ c. c₈h₄o₂\n○ d. c₄h₈o₂\n○ e. c₆h₈o₂

select the correct answer.\na compound has a molecular weight of 112.124 atomic mass units and the empirical formula c₃h₄o. what is the molecular formula of the compound?\nuse the periodic table to help you\n\n○ a. c₆h₈o\n○ b. c₉h₁₂o₃\n○ c. c₈h₄o₂\n○ d. c₄h₈o₂\n○ e. c₆h₈o₂

Answer

Explanation:

Step1: Calculate empirical - formula mass

The atomic masses of C = 12.01, H = 1.008, O = 16.00 from the periodic - table. For the empirical formula (C_3H_4O), the empirical - formula mass (M_{empirical}=(3\times12.01)+(4\times1.008)+16.00) [ \begin{align*} M_{empirical}&=36.03 + 4.032+16.00\ &=56.062 \end{align*} ]

Step2: Find the multiple (n)

The molecular weight (M_{molecular}=112.124). The multiple (n=\frac{M_{molecular}}{M_{empirical}}=\frac{112.124}{56.062}=2)

Step3: Determine the molecular formula

Multiply the sub - scripts in the empirical formula by (n = 2). The empirical formula is (C_3H_4O), so the molecular formula is (C_{3\times2}H_{4\times2}O_{1\times2}=C_6H_8O_2)

Answer:

E. (C_6H_8O_2)