simple binary ionic compounds\nplease complete the following table:\n| name of ionic compound | formula of…

simple binary ionic compounds\nplease complete the following table:\n| name of ionic compound | formula of ionic compound |\n| ---- | ---- |\n| 1. sodium bromide | nabr |\n| 2. calcium chloride | cacl₂ |\n| 3. magnesium sulfide | mgs |\n| 4. aluminum oxide | al₂o₃ |\n| 5. lithium phosphide | li₃p |\n| 6. cesium nitride | cs₃n |\n| 7. potassium iodide | ki |\n| 8. barium fluoride | baf₂ |\n| 9. rubidium nitride | rb₃n |\n| 10. barium oxide | bao |\n| 11. | k₂o |\n| 12. | mgi₂ |\n| 13. | alcl₃ |\n| 14. | cabr₂ |\n| 15. | na₃n |\n| 16. | lif |\n| 17. | ba₃p₂ |\n| 18. | cs₂s |\n| 19. | srf₂ |\n| 20. | nacl |

simple binary ionic compounds\nplease complete the following table:\n| name of ionic compound | formula of ionic compound |\n| ---- | ---- |\n| 1. sodium bromide | nabr |\n| 2. calcium chloride | cacl₂ |\n| 3. magnesium sulfide | mgs |\n| 4. aluminum oxide | al₂o₃ |\n| 5. lithium phosphide | li₃p |\n| 6. cesium nitride | cs₃n |\n| 7. potassium iodide | ki |\n| 8. barium fluoride | baf₂ |\n| 9. rubidium nitride | rb₃n |\n| 10. barium oxide | bao |\n| 11. | k₂o |\n| 12. | mgi₂ |\n| 13. | alcl₃ |\n| 14. | cabr₂ |\n| 15. | na₃n |\n| 16. | lif |\n| 17. | ba₃p₂ |\n| 18. | cs₂s |\n| 19. | srf₂ |\n| 20. | nacl |

Answer

Explanation:

Step1: Recall ion - charge rules

For binary ionic compounds, we determine the formula based on the charges of the cation and anion to ensure the compound is neutral. For example, sodium ($Na^+$) has a + 1 charge and bromide ($Br^-$) has a - 1 charge, so the formula of sodium bromide is $NaBr$.

Step2: Identify cations and anions

For calcium chloride, calcium ($Ca^{2 + }$) has a + 2 charge and chloride ($Cl^-$) has a - 1 charge. To balance the charges, we need 2 chloride ions for each calcium ion, so the formula is $CaCl_2$.

Step3: Determine correct sub - scripts

For aluminum oxide, aluminum ($Al^{3+}$) has a + 3 charge and oxide ($O^{2 - }$) has a - 2 charge. The least - common multiple of 3 and 2 is 6. So we need 2 aluminum ions ($2\times3 = 6$) and 3 oxide ions ($3\times2=6$) to balance the charges, giving the formula $Al_2O_3$. ... (continue this process for all compounds)

Answer:

Name of Ionic Compound Formula of Ionic Compound
1. Sodium bromide $NaBr$
2. Calcium chloride $CaCl_2$
3. Magnesium sulfide $MgS$
4. Aluminum oxide $Al_2O_3$
5. Lithium phosphide $Li_3P$
6. Cesium nitride $Cs_3N$
7. Potassium iodide $KI$
8. Barium fluoride $BaF_2$
9. Rubidium nitride $Rb_3N$
10. Barium oxide $BaO$
11. Potassium oxide $K_2O$
12. Magnesium iodide $MgI_2$
13. Aluminum chloride $AlCl_3$
14. Calcium bromide $CaBr_2$
15. Sodium nitride $Na_3N$
16. Lithium fluoride $LiF$
17. Barium phosphide $Ba_3P_2$
18. Cesium sulfide $Cs_2S$
19. Strontium fluoride $SrF_2$
20. Sodium chloride $NaCl$