t/f: for this skeleton equation, you get 1 mole of oxygen produced for every 1 mole of hgo: hgo -> hg +…

Explanation:

Step1: Balance the first equation

The balanced equation for $HgO\rightarrow Hg + O_2$ is $2HgO\rightarrow 2Hg+O_2$. From this, for every 2 moles of $HgO$, 1 mole of $O_2$ is produced, not 1 mole of $HgO$ for 1 mole of $O_2$. So the answer to the first - true/false question is false.

Step2: Define limiting reagent

The limiting reagent is the reactant that gets completely used up in the reaction. This is the definition of a limiting reagent. So the answer to the second - multiple - choice question is B.

Step3: Balance the third equation

For the equation $C_4H_{10}+O_2\rightarrow CO_2 + H_2O$, first balance the carbon atoms: $C_4H_{10}+O_2\rightarrow 4CO_2+H_2O$. Then balance the hydrogen atoms: $C_4H_{10}+O_2\rightarrow 4CO_2 + 5H_2O$. Finally, balance the oxygen atoms: $2C_4H_{10}+13O_2\rightarrow 8CO_2+10H_2O$. So the coefficients are 2, 13, 8, 10.

Answer:

False B. The reactant that gets completely used up in the reaction 2, 13, 8, 10