sno\nspell out the full name of the compound.\nview available hint(s)\n\n\nsubmit\n\npart b\ncr₂s₃\nspell…

sno\nspell out the full name of the compound.\nview available hint(s)\n\n\nsubmit\n\npart b\ncr₂s₃\nspell out the full name of the compound.\nview available hint(s)\n\n\nsubmit\n\npart c\nrbi\nspell out the full name of the compound.\nview available hint(s)

sno\nspell out the full name of the compound.\nview available hint(s)\n\n\nsubmit\n\npart b\ncr₂s₃\nspell out the full name of the compound.\nview available hint(s)\n\n\nsubmit\n\npart c\nrbi\nspell out the full name of the compound.\nview available hint(s)

Answer

Brief Explanations:

  1. For SnO: Tin can have +2 or +4 oxidation states. In SnO, tin has a +2 oxidation state. The naming convention for ionic compounds with a metal that can have multiple oxidation states is to use a Roman - numeral to indicate the oxidation state of the metal. So, it is tin(II) oxide.
  2. For Cr₂S₃: Chromium can have multiple oxidation states. In Cr₂S₃, each sulfur has a - 2 charge, and with 3 sulfurs having a total charge of -6. Since the compound is neutral, the total positive charge from 2 chromium atoms must be +6, so each chromium has a +3 oxidation state. It is named chromium(III) sulfide.
  3. For RbI: Rubidium is a group 1 metal with a +1 oxidation state and iodine is a halogen with a -1 oxidation state. For simple ionic compounds of group 1 metals and halogens, we just name the metal first and then the non - metal with the ending changed to 'ide'. So, it is rubidium iodide.

Answer:

Part A: Tin(II) oxide Part B: Chromium(III) sulfide Part C: Rubidium iodide