sodium hydroxide is extremely soluble in water. at a certain temperature, a saturated solution contains 527…

Explanation:

Step1: Calculate molar mass of NaOH

The molar mass of Na ($22.99\ g/mol$), O ($16.00\ g/mol$) and H ($1.01\ g/mol$). So, $M_{NaOH}=22.99 + 16.00+1.01=40.00\ g/mol$.

Step2: Calculate the number of moles of NaOH

Use the formula $n=\frac{m}{M}$, where $m = 527\ g$ and $M = 40.00\ g/mol$. So, $n=\frac{527\ g}{40.00\ g/mol}=13.175\ mol$.

Step3: Calculate the molarity

Molarity $M=\frac{n}{V}$, and $V = 1\ L$, $n = 13.175\ mol$. So, $M=\frac{13.175\ mol}{1\ L}=13.175\ M$.

Answer:

$13.175$