a student determines that she used 0.0665 mol of sodium hydroxide (naoh) to completely titrate 25.00 ml of…

a student determines that she used 0.0665 mol of sodium hydroxide (naoh) to completely titrate 25.00 ml of sulfuric acid solution (h₂so₄). what is the molarity of the sulfuric acid?\n0.00133 m\n0.00266 m\n1.33 m\n2.66 m

a student determines that she used 0.0665 mol of sodium hydroxide (naoh) to completely titrate 25.00 ml of sulfuric acid solution (h₂so₄). what is the molarity of the sulfuric acid?\n0.00133 m\n0.00266 m\n1.33 m\n2.66 m

Answer

Answer:

1.33 M

Explanation:

Step1: Write the balanced chemical equation

$$2NaOH + H_2SO_4=Na_2SO_4 + 2H_2O$$

Step2: Determine the mole - ratio

The mole - ratio of $NaOH$ to $H_2SO_4$ is $2:1$. So, if $n_{NaOH}=0.0665$ mol, then $n_{H_2SO_4}=\frac{n_{NaOH}}{2}=\frac{0.0665}{2}=0.03325$ mol.

Step3: Calculate the molarity of $H_2SO_4$

The volume of $H_2SO_4$ solution $V = 25.00$ mL $=0.025$ L. Using the molarity formula $M=\frac{n}{V}$, we have $M_{H_2SO_4}=\frac{0.03325}{0.025}=1.33$ M.