a student takes a sample of water with a salinity of 21 ‰ or psu and allows the water to evaporate, leaving…

a student takes a sample of water with a salinity of 21 ‰ or psu and allows the water to evaporate, leaving behind 21 grams of residual salts. the student then measured 11.56 grams of chloride ions in the salts. following the rule of constant proportions, how many grams of sodium ions were in the sample of water?

a student takes a sample of water with a salinity of 21 ‰ or psu and allows the water to evaporate, leaving behind 21 grams of residual salts. the student then measured 11.56 grams of chloride ions in the salts. following the rule of constant proportions, how many grams of sodium ions were in the sample of water?

Answer

Explanation:

Step1: Find the mass of sodium ions

We know that the total mass of residual salts is (m = 21\space g), and the mass of chloride ions is (m_{Cl}=11.56\space g). Let the mass of sodium ions be (m_{Na}). According to the principle that the sum of the masses of components in a mixture is equal to the mass of the mixture, we have the equation (m = m_{Na}+m_{Cl}).

Step2: Solve for (m_{Na})

Rearrange the equation (m = m_{Na}+m_{Cl}) to get (m_{Na}=m - m_{Cl}). Substitute (m = 21\space g) and (m_{Cl}=11.56\space g) into the equation: (m_{Na}=21 - 11.56) (m_{Na}=9.44\space g)

Answer:

(9.44)