students in mr. kleins chemistry class are conducting an experiment to calculate the specific heat of a…

students in mr. kleins chemistry class are conducting an experiment to calculate the specific heat of a copper sample. mr. klein requires each lab team to repeat the experiment until their percent error is 2% or less. percent error is calculated using observed values (those students calculate from their lab results) and the true value (the accepted value based on reference). the formula for percent error is: \n(observed - true) x 100 / true\nif the accepted value for the specific heat of copper is 0.385 j/g°c, which of the following lab teams have an unresolved problem on their hands?\n a. team 1: calculates 0.390 j/g°c\n b. team 2: calculates 0.395 j/g°c\n c. both teams\n d. neither team

students in mr. kleins chemistry class are conducting an experiment to calculate the specific heat of a copper sample. mr. klein requires each lab team to repeat the experiment until their percent error is 2% or less. percent error is calculated using observed values (those students calculate from their lab results) and the true value (the accepted value based on reference). the formula for percent error is: \n(observed - true) x 100 / true\nif the accepted value for the specific heat of copper is 0.385 j/g°c, which of the following lab teams have an unresolved problem on their hands?\n a. team 1: calculates 0.390 j/g°c\n b. team 2: calculates 0.395 j/g°c\n c. both teams\n d. neither team

Answer

Explanation:

Step1: Calculate percent - error for team 1

The formula for percent error is $\frac{\text{observed}-\text{true}}{\text{true}}\times100$. The true value of the specific heat of copper is $0.385\ J/g^{\circ}C$ and the observed value for team 1 is $0.390\ J/g^{\circ}C$. Percent error for team 1 = $\frac{0.390 - 0.385}{0.385}\times100=\frac{0.005}{0.385}\times100\approx1.299%$

Step2: Calculate percent - error for team 2

The observed value for team 2 is $0.395\ J/g^{\circ}C$. Percent error for team 2 = $\frac{0.395 - 0.385}{0.385}\times100=\frac{0.01}{0.385}\times100\approx2.598%$

Step3: Determine which team has an unresolved problem

Mr. Klein requires the percent error to be 2% or less. Team 1 has a percent error of approximately $1.299%$ (less than 2%) and team 2 has a percent error of approximately $2.598%$ (greater than 2%). So team 2 has an unresolved problem.

Answer:

B. team 2: calculates $0.395\ J/g^{\circ}C$