suppose a yttrium - 88 nuclide transforms into a strontium - 88 nuclide by absorbing an electron and…

suppose a yttrium - 88 nuclide transforms into a strontium - 88 nuclide by absorbing an electron and emitting a gamma ray. complete the nuclear chemical equation below so that it describes this nuclear reaction.\n square\rightarrow_{38}^{88}sr + _{0}^{0}gamma

suppose a yttrium - 88 nuclide transforms into a strontium - 88 nuclide by absorbing an electron and emitting a gamma ray. complete the nuclear chemical equation below so that it describes this nuclear reaction.\n square\rightarrow_{38}^{88}sr + _{0}^{0}gamma

Answer

Explanation:

Step1: Recall electron - capture reaction

In electron - capture, a proton in the nucleus combines with an electron to form a neutron. The atomic number decreases by 1 while the mass number remains the same.

Step2: Determine the initial nuclide

Strontium (Sr) has an atomic number of 38. Since the reaction is electron - capture and the product is strontium - 88, the initial nuclide must have an atomic number of 39 (because 39 - 1=38) and a mass number of 88. Yttrium (Y) has an atomic number of 39. So the initial nuclide is ${39}^{88}Y$. The electron is represented as ${ - 1}^0e$. The nuclear equation is ${39}^{88}Y+{ - 1}^0e\rightarrow_{38}^{88}Sr + _{0}^{0}\gamma$.

Answer:

${39}^{88}Y+{ - 1}^0e$