this system has an equilibrium constant of 50.5 at 448°c: h₂(g) + i₂(g) ⇌ 2hi(g). what is the reaction…

this system has an equilibrium constant of 50.5 at 448°c: h₂(g) + i₂(g) ⇌ 2hi(g). what is the reaction quotient, q, for this system when h₂=0.200 m, i₂=0.100 m, and hi=3.00 m?
Answer
Explanation:
Step1: Write reaction quotient formula
The reaction quotient $Q$ for the reaction $H_2(g)+I_2(g)\rightleftharpoons 2HI(g)$ is given by $Q = \frac{[HI]^2}{[H_2][I_2]}$.
Step2: Substitute given concentrations
Substitute $[H_2]=0.200\ M$, $[I_2]=0.100\ M$ and $[HI] = 3.00\ M$ into the formula: $Q=\frac{(3.00)^2}{0.200\times0.100}$.
Step3: Calculate the value of Q
$Q=\frac{9.00}{0.0200}=450$.
Answer:
$450$