the two half - reactions are given below.\n$2e^- + 2h_2o + hpo_3^{2-} \\rightarrow h_2po_2^- +…

the two half - reactions are given below.\n$2e^- + 2h_2o + hpo_3^{2-} \\rightarrow h_2po_2^- + 3oh^-$\n$4oh^- + n_2h_4 \\rightarrow n_2 + 4h_2o + 4e^-$\nwhat is the coefficient for the hydroxide ion in the combined balanced net ionic equation?

the two half - reactions are given below.\n$2e^- + 2h_2o + hpo_3^{2-} \\rightarrow h_2po_2^- + 3oh^-$\n$4oh^- + n_2h_4 \\rightarrow n_2 + 4h_2o + 4e^-$\nwhat is the coefficient for the hydroxide ion in the combined balanced net ionic equation?

Answer

again.

For the first half - reaction (multiplied by 2):

  • P: 2 on left, 2 on right (good)
  • O: (2\times3 + 4\times1=6 + 4 = 10) on left (2 (HPO_3^{2 - }) has 6 O, 4 (H_2O) has 4 O); on right, 2\times2+6\times1 = 4 + 6=10 O (2 (H_2PO_2^-) has 4 O, 6 (OH^-) has 6 O) (good)
  • H: 4\times2 + 2\times2=8 + 4 = 12? Wait, no, (2HPO_3^{2 - }) has 2 H, (4H_2O) has 8 H, total 10 H. On right, 2\times2+6\times1=4 + 6 = 10 H (2 (H_2PO_2^-) has 4 H, 6 (OH^-) has 6 H) (good)

Second half - reaction:

  • N: 2 on left, 2 on right (good)
  • H: 4 on left, 4\times2 = 8 on right? Wait, no, (N_2H_4) has 4 H, (4H_2O) has 8 H? No, (4H_2O) has 8 H? Wait, (N_2H_4\rightarrow4H_2O): (N_2H_4) has 4 H, (4H_2O) has 8 H.