an unbalanced chemical equation for the reaction of boron fluoride with lithium sulfite is shown below.\nbf₃…
an unbalanced chemical equation for the reaction of boron fluoride with lithium sulfite is shown below.\nbf₃ + li₂so₃ → b₂(so₃)₃ + lif\nwhat is the coefficient of lithium fluoride in the balanced chemical reaction?\no 1\no 3\no 4\no 6
Answer
Explanation:
Step1: Balance boron atoms
There are 2 boron atoms in $B_2(SO_3)_3$. So we put a 2 in front of $BF_3$: $2BF_3 + Li_2SO_3\rightarrow B_2(SO_3)_3+LiF$.
Step2: Balance lithium atoms
There are 2 lithium atoms in $Li_2SO_3$. To balance lithium in the product side for $LiF$, and considering the number of other atoms, we put a 6 in front of $LiF$. Also, we need to put a 3 in front of $Li_2SO_3$ to balance sulfur and oxygen atoms. The balanced equation is $2BF_3 + 3Li_2SO_3\rightarrow B_2(SO_3)_3+6LiF$.
Answer:
D. 6