undergoes oxidation with an excess of the o in the presence of water?
undergoes oxidation with an excess of the o in the presence of water?
Answer
Explanation:
Step1: Identify the type of alcohol
The given alcohol is a secondary alcohol as the -OH group is attached to a carbon atom that is bonded to two other carbon atoms.
Step2: Recall oxidation of secondary alcohol
When a secondary alcohol is oxidized with an excess of an oxidizing agent [O] in the presence of water, it is converted into a ketone. The general reaction for the oxidation of a secondary alcohol $R_1R_2CHOH$ is $R_1R_2CHOH+[O]\rightarrow R_1R_2C = O+H_2O$.
Step3: Analyze the products
The first option is a ketone which is the correct product of the oxidation of the given secondary alcohol. The second option is a wrong - structured ketone. The third option is an alkane (no oxidation product). The fourth option is a carboxylic acid (formed from primary - alcohol oxidation). The fifth option is an alkene (not an oxidation product of this alcohol).
Answer:
The first option (the ketone - structured compound)