(c) what volume of 0.20 m nacl(aq) contains 10.0 g of nacl (molar mass 58 g/mol)?

Explanation:

Step1: Calculate the number of moles of NaCl

Use the formula $n=\frac{m}{M}$, where $m$ is the mass and $M$ is the molar - mass. Given $m = 10.0\ g$ and $M=58\ g/mol$, then $n=\frac{10.0\ g}{58\ g/mol}\approx0.1724\ mol$.

Step2: Calculate the volume of the solution

Use the formula $V=\frac{n}{c}$, where $n$ is the number of moles and $c$ is the molarity. Given $n = 0.1724\ mol$ and $c = 0.20\ mol/L$, then $V=\frac{0.1724\ mol}{0.20\ mol/L}=0.862\ L$.

Answer:

$0.86\ L$ (rounded to two significant figures)