what volume of 1.25 m hcl reacts with 13.49 g al in the reaction below? 2al + 6hcl → 2alcl₃ + 3h₂ ? l hcl

Explanation:

Step1: Calculate moles of Al

Molar mass of Al is 26.98 g/mol. Moles of Al = mass / molar mass = ( \frac{13.49\ g}{26.98\ g/mol} ) ( \frac{13.49}{26.98} \approx 0.5\ mol )

Step2: Use stoichiometry to find moles of HCl

From the reaction ( 2Al + 6HCl \rightarrow 2AlCl_3 + 3H_2 ), the mole ratio of Al to HCl is 2:6 (or 1:3). So moles of HCl = 3 × moles of Al = 3 × 0.5 mol = 1.5 mol

Step3: Calculate volume of HCl solution

Molarity (M) = moles / volume (L), so volume (L) = moles / Molarity. Given M = 1.25 M, volume = ( \frac{1.5\ mol}{1.25\ mol/L} ) ( \frac{1.5}{1.25} = 1.2\ L )

Answer:

1.2