what volume of a 2.46 m magnesium nitrate (mg(no3)2) solution would be needed to make 275 ml of a 0.758 m…

what volume of a 2.46 m magnesium nitrate (mg(no3)2) solution would be needed to make 275 ml of a 0.758 m solution by dilution?\n? ml of 2.46 m mg(no3)2

what volume of a 2.46 m magnesium nitrate (mg(no3)2) solution would be needed to make 275 ml of a 0.758 m solution by dilution?\n? ml of 2.46 m mg(no3)2

Answer

Explanation:

Step1: Identify the dilution formula

$M_1V_1 = M_2V_2$

Step2: Define the variables

$M_1 = 2.46\ M$ (initial concentration), $V_1$ is the volume we want to find, $M_2=0.758\ M$ (final - concentration), $V_2 = 275\ mL$ (final volume).

Step3: Rearrange the formula to solve for $V_1$

$V_1=\frac{M_2V_2}{M_1}$

Step4: Substitute the values

$V_1=\frac{0.758\ M\times275\ mL}{2.46\ M}$ $V_1=\frac{208.45\ M\cdot mL}{2.46\ M}$ $V_1 = 84.8\ mL$

Answer:

84.8 mL