the volume of hydrogen gas is twice the volume of oxygen gas. what is the mass relationship between hydrogen…

Explanation:

Step1: Recall the ideal gas law

$PV = nRT$. At the same temperature ($T$) and pressure ($P$), the amount of gas ($n$) is proportional to the volume ($V$) since $R$ is a constant. So if $V_{H_2}=2V_{O_2}$, then $n_{H_2} = 2n_{O_2}$.

Step2: Calculate the mass of each gas

The mass ($m$) of a gas is given by $m=nM$, where $M$ is the molar - mass. The molar - mass of $H_2$ is $M_{H_2}=2\ g/mol$ and the molar - mass of $O_2$ is $M_{O_2} = 32\ g/mol$. So $m_{H_2}=n_{H_2}M_{H_2}$ and $m_{O_2}=n_{O_2}M_{O_2}$. Substituting $n_{H_2} = 2n_{O_2}$ into the mass formula for $H_2$, we get $m_{H_2}=2n_{O_2}\times2\ g/mol = 4n_{O_2}\ g/mol$, and $m_{O_2}=n_{O_2}\times32\ g/mol$.

Step3: Find the mass ratio

The ratio of the mass of $H_2$ to the mass of $O_2$ is $\frac{m_{H_2}}{m_{O_2}}=\frac{4n_{O_2}}{32n_{O_2}}=\frac{1}{8}$. So the hydrogen gas is $\frac{1}{8}$ as massive as the oxygen gas, which means more information (such as temperature and pressure conditions to be more precise in a non - standard situation) is required to accurately state the mass relationship in a general sense.

Answer:

More information is required.