what volume, in liters, of 0.023 m nh4no3 solution can be made using 25 g nh4no3? nh4no3: 80.043 g/mol

Explanation:

Step1: Calculate moles of NH₄NO₃

$n=\frac{m}{M}$, where $m = 25\ g$ and $M=80.043\ g/mol$. So $n=\frac{25\ g}{80.043\ g/mol}\approx0.3123\ mol$.

Step2: Calculate volume of solution

$V=\frac{n}{C}$, where $n = 0.3123\ mol$ and $C = 0.023\ M$. So $V=\frac{0.3123\ mol}{0.023\ mol/L}\approx13.6\ L$.

Answer:

$13.6$