what volume, in liters, of 0.023 m nh4no3 solution can be made using 25 g nh4no3? nh4no3: 80.043 g/mol ? l

Answer:

12.49 L

Explanation:

Step1: Calculate moles of NH4NO3

$n=\frac{m}{M}=\frac{25\ g}{80.043\ g/mol}\approx0.3123\ mol$

Step2: Calculate volume of solution

$V = \frac{n}{C}=\frac{0.3123\ mol}{0.023\ mol/L}\approx12.49\ L$