what volume in liters of a 0.724 m nai solution contains 0.405 mol of nai?

Explanation:

Step1: Recall molarity formula

Molarity ($M$) = $\frac{n}{V}$, where $n$ is the number of moles and $V$ is the volume in liters. We need to solve for $V$. Rearranging the formula gives $V=\frac{n}{M}$.

Step2: Substitute given values

We know that $n = 0.405$ mol and $M=0.724$ mol/L. Substituting these values into the formula $V=\frac{n}{M}$, we get $V=\frac{0.405\ mol}{0.724\ mol/L}$.

Step3: Calculate the volume

$V=\frac{0.405}{0.724}\ L\approx0.5608\ L$.

Answer:

$0.561$ L (rounded to three - significant figures)