what volume of a 2.5 m lithium nitrate solution would be needed to make 150 ml of a 1.0 m solution by…

what volume of a 2.5 m lithium nitrate solution would be needed to make 150 ml of a 1.0 m solution by dilution?\nm1 = 2.5 m v1 = ? ml\nm2 = 1.0 m v2 = 150 ml\nm1v1 = m2v2\n? ml lino3

what volume of a 2.5 m lithium nitrate solution would be needed to make 150 ml of a 1.0 m solution by dilution?\nm1 = 2.5 m v1 = ? ml\nm2 = 1.0 m v2 = 150 ml\nm1v1 = m2v2\n? ml lino3

Answer

Explanation:

Step1: Rearrange the dilution formula

We start with $M_1V_1 = M_2V_2$ and solve for $V_1$. So $V_1=\frac{M_2V_2}{M_1}$.

Step2: Substitute the given values

Substitute $M_1 = 2.5\ M$, $M_2 = 1.0\ M$, and $V_2=150\ mL$ into the formula. $V_1=\frac{1.0\ M\times150\ mL}{2.5\ M}$.

Step3: Calculate the value of $V_1$

$V_1 = 60\ mL$.

Answer:

60 mL